四行代码解决斐波那契数列

sja

其实就是通项公式（逃

a=eval(input("a="))
for n in range (1,a+1):
    b=((5**(0.5))/5)*((((1+(5**(0.5)))/2)**(n/1))-(((1-(5**(0.5)))/2)**(n/1)))
    print("%.0f"%b)