【每日一坑 3】 找数字

crossin先生

bingdashen 发表于 2016-8-8 20:18
新手试试水，楼主看看这个怎么样？
text="aAsmr3idd4bgs7DIsf9eAF"
a=list(text)

可以，你这是python3吧

bingdashen

crossin先生 发表于 2016-8-9 17:01
可以，你这是python3吧

对。

morpheus2222

text = "aAsmr3idd4bgs7Dlsf9eAF"
result = "".join([s for s in list(text) if s.isdigit()])
print(result)

jssngz

python 新手，正则还不会用 先用笨方法写出两种

1. text = "aAsmr3idd4bgs7Dlsf9eAF"
   
2. number = ''
   
3. for i in range(len(text)):
   
4.     char =text[i]
   
5.     if char.isdigit():
   
6.         # python的内建函数，判断是否是数字
   
7.         number += char
   
8. print(number)
   
9. # 第二种解决方法
   
10. text = "aAsmr3idd4bgs7Dlsf9eAF"
    
11. number = ''
    
12. for i in range(len(text)):
    
13.     char =text[i]
    
14.     try:
    
15.         int(char)
    
16.         number += char
    
17.     except ValueError:
    
18.         pass
    
19. print(number)

复制代码

zhaozihang

import re
text='aAsmr3idd4bgs7Dlsf9eAF'

print str(re.findall(r'\d+',text))

qingri

# 3
# find all the numbers and combine them to a new string
import re
text = "aAsmr3idd42bgs72Dlsf23eAF"
# regular expression find all the numbers which length greater equal than 1
nums = re.findall("[0-9]+",text)
# check the output
print nums
# join them together
new_str = ''.join(nums)
# check the type of new string
print type(new_str)
# print new string
print new_str

crossin先生

qingri 发表于 2017-6-7 23:22
# 3
# find all the numbers and combine them to a new string
import re

zaizaicaocao

text = "aAsmr3idd4bgs7Dlsf9eAF"
import re
num=re.findall('[0-9]+',text)
print(num)

zaizaicaocao

import re
text = "aAsmr3idd4bgs7Dlsf9eAF"

num=re.findall('[0-9]+',text)
print(num)

wolfog

def findDigit():
    for i in text:
        if i.isdigit():
            listStr.append(i)
text = "aAsmr3idd4bgs7Dlsf9eAF?*"
listStr = []
findDigit()

print "".join(listStr)