pytnon3，请教编码的错误问题

任侠澜

C大，这是我学习之后自己尝试改良的一个猜数游戏，代码能够执行，但是我却遇到了些逻辑问题，我自己无法判断原因，因此发在帖子中希望得到指点

预定设计功能：猜出设定数字，最多可以有5次机会。每猜完一次，显示剩余可用次数。

问题代码  ：
《《answer = int(input())#第一次输入数值


num = 66
global  times,rest
times = 0
while times < 4:
    rest=4-times
    if answer<num:
        times+=1
        print("bad,too small\n"
              "you have only %d chances rest\n"
              "give me the new answer"%rest)
        print(times,rest)
        
        answer=int(input())
    if  answer>num:
        times+=1
        print("Unlucky,too much\n"
              "you have only %d chances rest\n"
              "Guess again"%rest)
        print(times,rest)
        answer=int(input())
    if  answer==num:
        print("not bad kids,you made yourself a surviver")
        break
if times == 4:
    print("Stupid pigs,you have no value to live,die Die DIE !!")   #如果全部次数用完还没有猜对，输出
else:
    print("NOW,you can go ,I'll be here for the next ,HAHAHAHAHA") 》》#否则输出本行

问题描述：
通过将本代码第一行的“输入”，改入while循环内部，并删去数字不正确时的判定语句中的“输入”,并修改相关参数。可以完美运行预设目标，如下
num=66
global  times,rest
times = 0
while times < 5:
    rest=4-times
    answer=int(input())
    if answer<num:
        times+=1
        print("bad,too small\n"
              "you have only %d chances rest\n"
              "give me the new answer"%rest)
        print(times，rest)
      
    if  answer>num:
        times+=1
        print("Unlucky,too much\n"
              "you have only %d chances rest\n"
              "Guess again"%rest)
        print(times,rest)
        
    if  answer==num:
        print("not bad kids,you made yourself a surviver")
        break
if times == 5:
    print("Stupid pigs,you have no value to live,die Die DIE !!")
else:
    print("NOW,you can go ,I'll be here for the next ,HAHAHAHAHA")

但是原错误代码中的问题产生原因，我却不知道，主要有
1，如果猜测中，每次的数字都大于或者小于预设数66，则代码正常工作，但如果其中某次错误的猜大或者小了，下一次猜小了或者猜大了，rest的数值就会出错，具体如下

give me your answer!
77
Unlucky,too much
you have only 4 chances rest
Guess again
1 4
55
bad,too small
you have only 3 chances rest
give me the new answer
2 3
77
Unlucky,too much
you have only 3 chances rest
Guess again
3 3
55
bad,too small
you have only 1 chances rest
give me the new answer
4 1
77
Unlucky,too much
you have only 1 chances rest
Guess again
5 1
55
NOW,you can go ,I'll be here for the next ,HAHAHAHAHA
可以看到当答案摇摆时，times计数正常，但是rest却会依旧显示之前的数字，每两次之后又会输出正确值，但依然重复之前的错误

2，再times计数正常的情况下，while 判定失效，以至于可以输入6次答案（虽然第6次时，已经退出循环，不再进行条件判定）（然而，本当第5次就已经推出循环了）
3，如果5次猜测全部比设定值大或者小，第5次输入后应当不进行判断，直接输出“Stupid…”语句。但是，如果第五次输入正常答案，则会多输出“not bad kids …”一句，如下
give me your answer!
88
Unlucky,too much
you have only 4 chances rest
Guess again
1 4
88
Unlucky,too much
you have only 3 chances rest
Guess again
2 3
85
Unlucky,too much
you have only 2 chances rest
Guess again
3 2
84
Unlucky,too much
you have only 1 chances rest
Guess again
4 1
66
not bad kids,you made yourself a surviver
Stupid pigs,you have no value to live,die Die DIE !!
同样的，这种情况也会发生在问题1，描述的摇摆猜测情形之中，如下
give me your answer!
77
Unlucky,too much
you have only 4 chances rest
Guess again
1 4
45
bad,too small
you have only 3 chances rest
give me the new answer
2 3
75
Unlucky,too much
you have only 3 chances rest
Guess again
3 3
36
bad,too small
you have only 1 chances rest
give me the new answer
4 1
88
Unlucky,too much
you have only 1 chances rest
Guess again
5 1
66
not bad kids,you made yourself a surviver
NOW,you can go ,I'll be here for the next ,HAHAHAHAHA
也就是说，实际上第五次之后，如果答案正确，while 会依旧执行一次整体判断。这理论上应该不会发生才对。
对于这3个问题，我思考许久得不出答案，因此向你请教，还希望你能在百忙之中抽出一点时间，帮我解答疑惑。非常感谢

crossin先生

你是if，不是elif，第一个if执行完，还会继续向下执行。你用断点或者print仔细看看程序是怎样一步一步执行的，理解下执行的顺序