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标题: 第27课点球小游戏BUG? [打印本页]

作者: wujinyekong 时间: 2017-9-5 17:09
标题: 第27课点球小游戏BUG?
本帖最后由 wujinyekong 于 2017-9-5 17:12 编辑

from random import choice

score_you = 0

score_com = 0

direction = ['left', 'center', 'right']

for i in range(5):

print '==== Round %d - You Kick! ====' % (i+1)

print 'Choose one side to shoot:'
print 'left, center, right'
you = raw_input()

print 'You kicked ' + you

com = choice(direction)

print 'Computer saved ' + com

if you != com:

   print 'Goal!'
score_you += 1

else:

   print 'Oops...'
print 'Score: %d(you) - %d(com)\n' % (score_you, score_com)

print '==== Round %d - You Save! ====' % (i+1)

print 'Choose one side to save:'
print 'left, center, right'
you = raw_input()

print 'You saved ' + you

com = choice(direction)

print 'Computer kicked ' + com

if you == com:

   print 'Saved!'
else:

   print 'Oops...'
score_com += 1

print 'Score: %d(you) - %d(com)\n' % (score_you, score_com)

按照这个代码，可以随便写一个['left', 'center', 'right']之外的字符，都判定电脑没守中。

我想知道
if you != com:
   print 'Goal!'
score_you += 1
这个判断句说的啥？求指导

屏幕快照 2017-09-05 下午5.03.54.png (56.35 KB, 下载次数: 387)

屏幕快照 2017-09-05 下午5.03.54.png

作者: crossin先生 时间: 2017-9-5 21:13
你说的对，这个代码并不完善，你可以自行完善它

作者: wujinyekong 时间: 2017-9-6 10:44
本帖最后由 wujinyekong 于 2017-9-6 10:46 编辑

crossin先生发表于 2017-9-5 21:13
你说的对，这个代码并不完善，你可以自行完善它

from random import choice

score = [0,0]
direction = ['left','center','right']

def kick():
print '=====You Kick!====='
print 'Choose one side to shoot:'
print 'left,center,right'
you = raw_input()
print 'You kicked ' + you
com = choice(direction)
if you != 'left' and you != 'center' and you != 'right':
      print 'Game over!Spell right!'
      exit()
else:
      if you == com:
         print 'Opps...'
      else:
         print 'Goal!'
         score[0]+=1
print 'Score:%d(you)-%d(com)\n'%(score[0],score[1])

print '=====You Save!====='
print 'Choose one side to save'
print 'left,center,right'
you = raw_input()
print 'You save ' + you
com=choice(direction)
if you != 'left' and you != 'center' and you != 'right':
      print 'Game over!Spell right!'
      exit()
else:
      if you == com:
         print 'Saved!'
      else:
         print 'Opps...'
         score[1]+=1
print 'Score:%d(you)-%d(com)\n'%(score[0],score[1])

for i in range(5):
print '=====Round %d====='%(i+1)
kick()

while(score[0]==score[1]):
i +=1
print'=====Round %d====='%(i+1)
kick()

if score[0]>score[1]:
print 'You Win!'
else:
print 'You Lose.'

我加了判断语句，当出现非正确方向是结束程序。
可是我希望加一个语句，输入错误时，提示错误并重新重输入后继续。求指点一下，应该用什么语句？

作者: wujinyekong 时间: 2017-9-6 10:54

wujinyekong 发表于 2017-9-6 10:44
from random import choice

score = [0,0]

from random import choice

score = [0,0]
direction = ['left','center','right']

def kick():
print '=====You Kick!====='
print 'Choose one side to shoot:'
print 'left,center,right'
you = raw_input()
while you != 'left' and you != 'center' and you != 'right':
      print 'Choose again!Spell right!'
      you = raw_input()
print 'You kicked ' + you
com = choice(direction)
if you == com:
      print 'Opps...'
else:
      print 'Goal!'
      score[0]+=1
print 'Score:%d(you)-%d(com)\n'%(score[0],score[1])

print '=====You Save!====='
print 'Choose one side to save'
print 'left,center,right'
you = raw_input()
while you != 'left' and you != 'center' and you != 'right':
      print 'Choose again!Spell right!'
      you = raw_input()
print 'You save ' + you
com = choice(direction)
if you == com:
      print 'Saved!'
else:
      print 'Opps...'
      score[1]+=1
print 'Score:%d(you)-%d(com)\n'%(score[0],score[1])

for i in range(5):
print '=====Round %d====='%(i+1)
kick()

while(score[0]==score[1]):
i +=1
print'=====Round %d====='%(i+1)
kick()

if score[0]>score[1]:
print 'You Win!'
else:
print 'You Lose.'

自问自答了……有while语句就可以了……

作者: wujinyekong 时间: 2017-9-6 10:58
那我又有一个问题，判断 you 是不是 direction 的子集，有没有直接的判断语句，类似于集合中的包含于，这种符号？

作者: crossin先生 时间: 2017-9-7 14:54

wujinyekong 发表于 2017-9-6 10:58
那我又有一个问题，判断 you 是不是 direction 的子集，有没有直接的判断语句，类似于集合中的包含于，这种 ...

if you in direction:

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