【每日一坑 3】 找数字

歪脑特

初学者，用笨方法实现的

1. text = "aAsmr3idd4bgs7Dlsf9eAF"
   
2. num = ''
   
3. 
   
4. for i in range(len(text)):
   
5.     if text[i].isnumeric():
   
6.         num += text[i]
   

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byron

1. text = "aAsmr3idd4bgs7Dlsf9eAF"
   
2. #只保留数字
   
3. list(filter(str.isdigit, text))
   
4. #只保留字母
   
5. list(filter(str.isalpha, text))

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xuefu

1. #include <stdio.h>
   
2. #include <string.h>
   
3. #include <sys/types.h>
   
4. 
   
5. int main(int argc, const char *argv[])
   
6. {
   
7.   char *s;
   
8.   int len;
   
9. 
   
10.   s = "aAsmr3idd4bgs7Dlsf9eAF";
    
11.   len = strlen(s);
    
12. 
    
13.   int i;
    
14.   for (i = 0; i < len; i++)
    
15.   {
    
16.     if (isdigit(s[i]))
    
17.       printf("%c", s[i]);
    
18.   }
    
19. 
    
20.   printf("\n");
    
21. 
    
22.   return 0;
    
23. }
    

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fl0w

NewString.py

1. #! /usr/bin/env python
   
2. # coding:utf-8
   
3. 
   
4. import sys
   
5. 
   
6. if __name__ == "__main__":
   
7.     if len(sys.argv) == 1:
   
8.         print 'Please Input like this:./NewString.py aAsmr3idd4bgs7Dlsf9eAF'
   
9.     else:
   
10.         originString = sys.argv[1]
    
11.         digitalList = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
    
12.         newString = ''.join([i for i in originString if i in digitalList])
    
13.         print newString

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nodejx

1. #!/usr/bin/env python
   
2. # -*- coding: utf-8 -*-
   
3. # Copyright 2013 nodejx
   
4. text = "aAsmr3idd4bgs7Dlsf9eAF"
   
5. NewString=''.join([i for i in text if i.isdigit()])
   
6. print NewString

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caven

1. import re
   
2. 
   
3. text = "aAsmr3idd4bgs7Dlsf9eAF"
   
4. print ''.join(re.findall(r'[\d|.]+',text))

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近猪者痴

正则表达式

re.findall(r'[\d|.]+',text)